Suggested: tan^2(2x-3) integral - tan 2(2x-3) - nth derivative of tan inverse 2x/1-x^2 - u=tan^-1(2xy/x^2-y^2) - (2xy+y-tan y)dx+(x^(2)-x tan^(2)y+sec^(2)y)dy=0 - tan inverse 2x/1-x^2 - tan inverse 3a^2x-x^3/a^3-3ax^2 - if y=tan^(-1)(2x)/(1-x^(2)) find dy/dx - tan^2x+cot^2x=2 - derivative of 2sec^2x tanx - tan^2(2x Browse related:
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